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(D) The reaction between two molecules of acetone $(CH_3COCH_3)$ in the presence of dilute $NaOH$ is an Aldol condensation reaction.In this reaction,o

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$4-$Hydroxy$-4-$methyl$-2-$pentanone

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(D) The reaction between two molecules of acetone $(CH_3COCH_3)$ in the presence of dilute $NaOH$ is an Aldol condensation reaction.In this reaction,one molecule of acetone acts as a nucleophile (enolate ion) and attacks the carbonyl carbon of another acetone molecule.The reaction proceeds as follows:$2 CH_3COCH_3 \xrightarrow{dil. NaOH} (CH_3)_2C(OH)CH_2COCH_3$The product formed is $4-$hydroxy$-4-$methylpentan$-2-$one,which is also known as diacetone alcohol.

Two molecules of acetone in the presence of dilute $NaOH$ give the product:

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